2x^2-5x-40=2

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Solution for 2x^2-5x-40=2 equation:


Simplifying
2x2 + -5x + -40 = 2

Reorder the terms:
-40 + -5x + 2x2 = 2

Solving
-40 + -5x + 2x2 = 2

Solving for variable 'x'.

Reorder the terms:
-40 + -2 + -5x + 2x2 = 2 + -2

Combine like terms: -40 + -2 = -42
-42 + -5x + 2x2 = 2 + -2

Combine like terms: 2 + -2 = 0
-42 + -5x + 2x2 = 0

Factor a trinomial.
(-7 + -2x)(6 + -1x) = 0

Subproblem 1

Set the factor '(-7 + -2x)' equal to zero and attempt to solve: Simplifying -7 + -2x = 0 Solving -7 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -2x = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -2x = 0 + 7 -2x = 0 + 7 Combine like terms: 0 + 7 = 7 -2x = 7 Divide each side by '-2'. x = -3.5 Simplifying x = -3.5

Subproblem 2

Set the factor '(6 + -1x)' equal to zero and attempt to solve: Simplifying 6 + -1x = 0 Solving 6 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + -1x = 0 + -6 Combine like terms: 6 + -6 = 0 0 + -1x = 0 + -6 -1x = 0 + -6 Combine like terms: 0 + -6 = -6 -1x = -6 Divide each side by '-1'. x = 6 Simplifying x = 6

Solution

x = {-3.5, 6}

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